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DOE, General Matter team up for new fuel mission at Hanford
The Department of Energy's Office of Environmental Management (EM) on Tuesday announced a partnership with California-based nuclear fuel company General Matter for the potential use of the long-idle Fuels and Materials Examination Facility (FMEF) at the Hanford Site in Washington state.
According to the announcement, the DOE and General Matter have signed a lease to explore the FMEF's potential to be used for advanced nuclear fuel cycle technologies and materials, in part to help satisfy the predicted future requirements of artificial intelligence.
F. C. Schoenig, K. S. Quisenberry, D. P. Stricos, and H. Bernatowicz
Nuclear Science and Engineering | Volume 26 | Number 3 | November 1966 | Pages 393-398
Technical Paper | doi.org/10.13182/NSE66-A17362
Articles are hosted by Taylor and Francis Online.
The temperature dependence of the thorium-oxide resonance integral has been measured over a wide (20 to 1550 °C) temperature range. The activation method was used; the 310 keV γ ray from the decay of 233Pa was measured with a multichannel pulse-height analyzer. Measurements were performed on ThO2 rods of 0.490− and 0.353−in. diam. (surface-to-mass ratio = 0.340 and 0.465 cm2/g, respectively). The temperature dependence of the thorium-oxide resonance integral was found not to be a linear function of either (t − t0) or (√T − √T0), where t and T and centigrade and Kelvin temperature, and t0 and T0 are 20°C, and 293°K, respectively. Thus the familiar forms of the temperature dependence of the effective resonance integral, namely RI(T)/RI(T0) = 1 + α (t − t0) = 1 + β × (√T − √To) are not appropriate representations of the data. The Doppler coefficient in a 1/E spectrum is defined by α0 = [1/RI(T)] [dRI(T)/ dT] where RI(T) is the effective resonance integral of the sample excluding the 1/v contribution, and T is the temperature of the sample. It has been found that α0 = [(0.16 ± 0.01)/T] yields a good fit to the experimental data of both sample sizes. It follows that RI(T) = RI(T0) (T/T0)(0.16 ± 0.01).